The discussion revolves around the dynamics of a yoyo, specifically focusing on its downward acceleration as it unwinds from a fixed string. The subject area includes concepts from rotational motion and forces acting on rigid bodies.
Some participants have provided mathematical expressions related to the yoyo's acceleration, while others are exploring the implications of these equations. There is ongoing inquiry regarding the acceleration of a slipping cylinder, indicating a productive exploration of related concepts.
Participants are navigating the complexities of rotational dynamics and friction, with specific attention to the assumptions made about the yoyo's structure and the conditions of the slipping cylinder scenario.
If the yo-yo is just a uniform disk with the string wound around the rim, this answer can be simplified.deanwudean said:I got it ,F=(M+lc/(R^2))ac
Mg=ac(M+(1/2MR^2)/(r^2)
ac=g/(1+R^2/2r^2)
Just add the friction force to the mix. It equals [itex]\mu N[/itex].just one more question, I can't figure out the accerlation of a slipping cylinder in a ramp.
how to apply slipping force, I mean the kinetic frictional force>?