What is the Efficiency of a Gas Machine in an A->B->C Change?

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The discussion focuses on calculating the heat transfer (Q) and the efficiency of a gas machine during an A->B->C process. The user attempts to apply the work formula W=pV but encounters difficulties in obtaining useful results, particularly from the A to B transition where W equals zero. They recognize the need for additional variables such as the number of moles of gas, the gas constant R, and temperature values to calculate Q effectively. The relationship ΔU = ΔQ + ΔW is mentioned as a potential method for determining heat transfer. Overall, the conversation highlights the complexities involved in thermodynamic calculations for gas machines.
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Homework Statement



The task is to get Q, that gas has received through A-B-C change?
Second task is to get usefulness of the machine?

http://img40.imageshack.us/img40/8372/toplinaabc.jpg

Homework Equations



W=pV

The Attempt at a Solution



If I use W=pV i get 0 from A->B so i can't get usefulness. No idea.
 
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To get the heat energy in or out of system one requires the value of the number of moles of gas and the gas constant R or the temperatures at some points on the graph.
 
So from A->B formula is PV=nRT then I get dT=((p2-p1)*v1)/nR?

from B->C formula is W=p2(v2*v1) and with ideal gas dT=(p2(v2-v1))/nR?

But how to get Q from that?
 
the_man said:
So from A->B formula is PV=nRT then I get dT=((p2-p1)*v1)/nR?

from B->C formula is W=p2(v2*v1) and with ideal gas dT=(p2(v2-v1))/nR?

But how to get Q from that?

from A->B formula is PV=nRT then I get dT=((p2-p1)*v1)/nR ...yes

from B->C formula is W=p2(v2*v1) ...replace * by -

dT=(p2(v2-v1))/nR ...yes

To get the heat transfer one can use \DeltaU = \DeltaQ + \DeltaW where U is the internal energy.
 
okay man, thanks!
 
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