What is the Electric Field at a Small Distance from a Charged Ring?

AI Thread Summary
To find the electric field at a small distance from the center of a charged ring, the charge distribution must be considered, especially since the Gaussian surface approach may not yield useful results due to the zero enclosed charge. Instead of using Gauss's law, it's recommended to integrate the electric field contributions from each segment of the ring. An alternative approach is to calculate the electric potential, which may simplify the problem. The correct expression for the electric field at a distance r from the center of the ring is given by Qr/(8πε₀a³). Understanding the geometry and symmetry of the problem is crucial for deriving the correct solution.
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Homework Statement



I have a ring, radius a, with a charge distributed evenly around it. Using a gaussian cylinder of radius r, r<<a (or otherwise). Find the electric field at at small distance r away from the centre of the ring, r is in the plane of the ring.

I know that the answer is

\frac{Qr}{8\pi\epsilon_0 a^3}



Homework Equations



\int E\cdot ds = Q/\epsilon_0


The Attempt at a Solution



I can't get started since I find that the charge enclosed is 0

Thanks
 
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Don't try to use Gauss's law. (What would be your Gaussian surface? Is the field uniform across it?) Instead, integrate the field contributions from each part of the ring. (It might prove easier to work with the potential instead of the field.)
 
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