What is the Electric Field at Position D on the Equipotential Surfaces?

AI Thread Summary
To determine the electric field at position D on the equipotential surfaces, the equation E = -ΔV/ΔS is used, where ΔV represents the potential difference between two points and ΔS is the distance between them. The grid lines indicate a distance of 2.0 cm, which should be considered when calculating ΔS. The electric field cannot be precisely defined but can be approximated by selecting the two nearest equipotential points above position D. The direction of the electric field will point from higher to lower potential, which can be inferred from the orientation of the equipotential surfaces. This approach allows for an estimation of both the magnitude and direction of the electric field at position D.
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Homework Statement


The drawing shows a graph of a set of equipotential surfaces in cross section. The grid lines are 2.0 cm apart. Determine the magnitude and direction of the electric field at position D.
Specify whether the electric field points toward the top or the bottom of the drawing.
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Homework Equations


E=-ΔV/ΔS
d=2.0x10-3

The Attempt at a Solution



I am uncertain how to solve for this problem, ΔV is usually between 2 variables, final - initial. Do I repeat this process for each field above point D?
 
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Guys, help?
 
7411 said:
Guys, help?

You can't say EXACTLY what the E field is. You can only approximate it. I would pick the two nearest points on the equipotential lines and work from there.
 

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