What is the Electric Potential at the Centre of a Charged Hollow Metal Sphere?

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The electric potential at the center of a charged hollow metal sphere is equal to the potential on its surface due to the properties of conductors. Inside a conductor, the electric field is zero, leading to a constant electric potential throughout the interior. By applying Gauss' Law, it can be determined that the potential just outside the sphere is -V. Therefore, the electric potential at the center of the sphere is also -V. This confirms that the answer to the question is option (a) -V.
drixz
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Hi there,

confused with a question ... does anyone knows the solution or answer for the following question ?

"The electric potential at the centre of a hollow metal sphere, radius 2m, which has been charged to a potential -V. is : (a)-V (b)-2V (c)2V (d)0 (e)V"
 
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Consider these ideas/questions:

What is the electric field inside a conductor?
How does the electric field relate to the electric potential (voltage)?
The electric potential function obeys spatial continuity (no jumps).
What is the electric potential just outside the sphere (use Gauss' Law and symmetry).
 
oh yeah ... thanks for the clue :)
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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