What is the equation for the kinetic energy of a pendulum at any point?

AI Thread Summary
The discussion focuses on deriving the kinetic energy equation for a pendulum at any point, starting from its initial angle. The user differentiates the angular position function to find angular velocity but questions the validity of their kinetic energy formula. Clarification is provided that the formula may be correct but could depend on whether an exact solution or a small angle approximation is desired. The conversation highlights the distinction between exact equations and simplified models in pendulum motion analysis. Understanding the context of the desired solution is crucial for accurately calculating kinetic energy.
velo city
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Homework Statement


I want to find the equation of the kinetic energy of a pendulum at any point. I know the initial angle it is released from but I am having trouble finding the velocity at any point to be able to find the kinetic energy at any point.



Homework Equations



θ = θmaxcos(w*t) where w = √g/L

I = mL2

KErotational=(1/2) *I(\frac{dθ}{dt})2






The Attempt at a Solution



I differentiated the θ function with respect to time to get dθ/dt

\frac{dθ}{dt}=-θmax*w*sin(w*t)

I have plugged that into find the kinetic energy but that's apparently not the right answer.
 
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L is the length of the pendulum by the way.
 
After plugging In I have found that the kinetic energy at any point is:

KE = m*L2max2*w2*sin2(w*t)
 
may i know how u conclude it to be the wrong answer ?
 
There is nothing wrong with your formula. why do you say it's wrong?
 
velo city said:
I want to find the equation of the kinetic energy of a pendulum at any point. I know the initial angle it is released from but I am having trouble finding the velocity at any point to be able to find the kinetic energy at any point.
It depends whether you want the exact equation or the SHM approximation for small angle displacements (which is what you posted).
For the question as stated, you could provide the exact answer. Maybe that's what's wanted here.
 
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