What Is the Fake Gravity on a Circular Space Hotel Orbiting Earth?

AI Thread Summary
A circular space hotel with a radius of 220m aims to create artificial gravity by achieving a centripetal acceleration of 9.81 m/s². The tangential speed required for this acceleration is calculated to be approximately 46.456 m/s, with an angular velocity of 0.211 radians per second. For a point 77m from the outer rim, resulting in a new radius of 143m, the centripetal acceleration would need to be recalculated using the appropriate equations. The discussion emphasizes the importance of understanding how acceleration changes with varying radius within the space station. Overall, the calculations and concepts of artificial gravity in a rotating space environment are explored.
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Homework Statement



A circular space hotel in orbit around the Earth has a radius of 220m. in order to produce "fake gravity" along the outer rim, it is desired to rotate at a speed that will produce a centripetal acceleration of 9.81 m/s^2.
A) find the tangential speed of appoint on the rim when the station is producing the required centripetal acceleration.
B) Find the station's angular velocity under those conditions, in radians per second.
C) If you're "below deck" at a point 77m from the outer rim, how much "gravity" will you experience?
D) If you start moving from the rim toward the central hub of the space station, what will it feel like? How will your perception change as you move?

Homework Equations



vt = √(ac*r)
ῳ = v/r

The Attempt at a Solution



A) I interpreted the following: ac = 9.81m/s^2 and r= 220m. With these I plugged into the first equation to find the tangential velocity which came out to be vt=46.456m/s.

B) To find the angular velocity I plugged in the vt and r in the second relevant equation and found ῳ=0.211rad/s.

C) Assuming I did the first two parts correctly (let me know if I did not please), this is what's giving me a problem. If 77 m "below deck" that would give you a new radius of 143m. I believe this would change your ac or completely eliminate it. Would the following equation work: ac = rῳ2?
I'm open to discuss this back and forth rather than just asking for help or an answer.
 
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anthonyslvtr said:
Would the following equation work: ac = rῳ2?
Yes.
 
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