What is the final temperature of the mixture?

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SUMMARY

The final temperature of the mixture, calculated using the principle of conservation of energy, is approximately 20.81 degrees Celsius. The experiment involves 1.1 kg of aluminum heated to 92 degrees Celsius and mixed with 0.5 kg of water at 12 degrees Celsius. The heat lost by aluminum equals the heat gained by water, leading to the equation (1.1)(880)(92-t) = (0.5)(4200)(t-12). The solution reveals an arithmetic error in the original calculation, emphasizing the importance of verifying each step in the process.

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Homework Statement


In an experiment, 1.1kg of aluminium is heated to 92 degrees Celsius it is then dropped into 0.5kg of water at 12 degrees celsius.

Find the final temperature of the mixture. (Cw= 4200JKg-1Celsius-1) (Cal= 880JKg-1Celsius-1)

Homework Equations


Qal = Qw

The Attempt at a Solution


(1.1)(880)(92-t) = (0.5)(4200)(t-12)
968( 92 - t ) = 2100( t - 12 )
89056-968t = 2100t - 25200
63856 = 3068t
20.81 = t
 
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No.

As you suspected, I suppose.

You can check your answers yourself: if you put back "t=20.81" in the first line of your equation, you will see that you are way off.
From your second line, one can see that cooling and heating have a ratio of about 2:1 in temperature.
 
Last edited:
Byeongok said:

Homework Statement


In an experiment, 1.1kg of aluminium is heated to 92 degrees Celsius it is then dropped into 0.5kg of water at 12 degrees celsius.

Find the final temperature of the mixture. (Cw= 4200JKg-1Celsius-1) (Cal= 880JKg-1Celsius-1)

Homework Equations


Qal = Qw

The Attempt at a Solution


(1.1)(880)(92-t) = (0.5)(4200)(t-12)
968( 92 - t ) = 2100( t - 12 )
89056-968t = 2100t - 25200
63856 = 3068t
Your problem lies in the arithmetic used to get the line immediately above.

Always check your work for arithmetic mistakes.
 

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