What is the fluid velocity in a restriction using Bernoulli's principle?

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Homework Help Overview

The discussion revolves around fluid dynamics, specifically applying Bernoulli's principle to determine fluid velocity in a restriction and pressure changes in varying pipe diameters. Participants are exploring scenarios involving liquid flow through pipes with different diameters and the implications of these changes on velocity and pressure.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply Bernoulli's equation but is uncertain about using diameter versus radius for height and whether pressures can be canceled. Others suggest using the continuity equation (A1v1 = A2v2) as a simpler approach to find fluid velocity in the restriction.

Discussion Status

Participants are actively engaging with the problems, with some providing guidance on using the continuity equation alongside Bernoulli's principle. There is a recognition of the need for clarification on certain assumptions, such as the relationship between pressure and radius in the second problem, indicating a productive exploration of the concepts.

Contextual Notes

Some participants express confusion regarding the application of Bernoulli's principle when multiple variables are unknown, highlighting the complexity of the problems presented. There is an emphasis on the need for hints rather than direct solutions, aligning with the forum's learning-first approach.

fro
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Liquid flows through a 4cm diameter at 1m/s. There is 2cm diameter restriction i n the line. Find fluid velocity in restriction.

[tex]p_1+ \rho\cdot g \cdot y_1 + \frac{1}{2}\rho \cdot(v_1)^2 = p_2+ \rho \cdot g\cdot y_2 + \frac{1}{2}\cdot \rho\cdot(v_2)^2[/tex]

I know I have to use Bernoulli's principle to solve this. I am confused as to if I use the diameter or radius in the problem for the height. Can I cancel out p1 and p2?
 
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Unless I'm missing something, you could solve this by simply stating A1v1 = A2v2, where A1 and A2 are the areas of the cross sections of the pipe.
 
radou said:
Unless I'm missing something, you could solve this by simply stating A1v1 = A2v2, where A1 and A2 are the areas of the cross sections of the pipe.

Thanks, I got it.
 
Here is a slightly different one:
Water flows at 12m/s with pressure of 3X10^4 N/m^2. If the pipe widens to twice its original radius, what is the pressure in the wider section?

I am trying to plug everything to Bernoulli's principle. Problem is that both the pressure and radius is unknown. Any hints as to how I should start this problem? Thanks.
 
fro said:
Here is a slightly different one:
Water flows at 12m/s with pressure of 3X10^4 N/m^2. If the pipe widens to twice its original radius, what is the pressure in the wider section?

I am trying to plug everything to Bernoulli's principle. Problem is that both the pressure and radius is unknown. Any hints as to how I should start this problem? Thanks.

Again, use the equation (i.e. conservation of mass) you used to solve the first problem, and then you'll have everything you need to apply Bernoulli's equation and solve for the pressure in the wider section.
 

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