What is the Force and Tension in a Helicopter Truck Rescue?

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The discussion focuses on calculating the forces involved in a helicopter lifting a truck during a rescue operation. The total mass being lifted is 19,500 kg, and the upward acceleration is 1.4 m/s². The participants debate the correct application of Newton's second law, particularly how to account for gravitational force and acceleration in opposite directions. It is clarified that the gravitational acceleration should be considered negative when defining upward as positive, while the upward acceleration remains positive. The conversation emphasizes the importance of correctly interpreting forces and accelerations in the context of the problem.
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After an incident over the mid-semester break involving a packet of Maltesers, a flooded creek,
and a wombat, a 15,000 kg salvage helicopter is lifting a 4,500 kg truck with an upward
acceleration of 1.4 m.s-2. Calculate:
1) The force the air exerts on the helicopter blades.
2) The tension in the cable between the truck and the helicopter

1. F = ma, so we know the mass is (15000 + 4500)

and would the acceleration be (9.8 + 1.4)?

2. Would T = m1*g + m1a?
 
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The accelerations are in opposite directions. If you define the direction up as positive then g = -9.8 m/s^2.
 
Corneo said:
The accelerations are in opposite directions. If you define the direction up as positive then g = -9.8 m/s^2.
Yes, but will the 1.4 be negative as well because the overall acceleration should be greater than 9.8?
 
No, the acceleration is what it is: 1.4m/s^2. You can take the upward direction as positive, so any downward pointing force is negative, and any upward pointing force is positive.
 
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