What is the force exerted on a car and driver during acceleration?

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To determine the force exerted on a car and driver during acceleration, first calculate the total mass, which is 1025 kg (950 kg for the car and 75 kg for the driver). The car accelerates from rest to 50.0 km/h, which converts to approximately 13.89 m/s. The acceleration can be calculated using the formula a = (final velocity - initial velocity) / time, resulting in an acceleration of about 1.63 m/s². Using Newton's second law (F = ma), the total force exerted on the car and driver is approximately 1671.25 N. Understanding the correct application of units and formulas is crucial for solving this problem accurately.
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A 950 kg car starts from rest and reaches a velocity of 50.0 km/h in 8.50 s. If the driver has a mass of 75.0 kg, what force is exerted on the car and driver during this time interval?

I am very confused on this question. I was thinking:

950kg+750.kg=1025
50.0/3.6 =13.88 +8.5 = 22.38s

1025/22.38 ... but obviously all of that is wrong seeing as how it doesn't give me any of answers I can choose from :( help! what am i doing wrong
 
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Brittykitty said:
A 950 kg car starts from rest and reaches a velocity of 50.0 km/h in 8.50 s. If the driver has a mass of 75.0 kg, what force is exerted on the car and driver during this time interval?

I am very confused on this question. I was thinking:

950kg+750.kg=1025
the mass of the car and driver is 1025 kg, OK
50.0/3.6 =13.88
please watch your units, 13.88 m/s is the velocity of the car after 8.5 seconds, then its acceleration is v/t, not v + t, and
1025/22.38
Where does this this formula come from? Please write out your relevant equations.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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