What is the force of contact between the two blocks?

AI Thread Summary
The discussion centers on calculating the force of contact between two blocks on a horizontal table when a force is applied at a 30-degree angle. The first block has a mass of 2.00 kg and the second block has a mass of 1.00 kg, with a total applied force of 60N and a kinetic friction coefficient of 0.250. Participants emphasize the importance of using free body diagrams (FBDs) for each block to analyze the forces acting on them. The inquiry highlights the complexity of the problem due to the interaction between the two blocks. Understanding the forces involved is crucial for determining the contact force accurately.
boupidou
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What is the force of contact between the two blocks?
Two blocks are in contact on a horizontal table. A force is applied on one of the blocks at a 30 degree angle (from the horizontal). The system moves towards the right. M1 = 2,00 kg and m2 = 1,00 km and F=60N and the kinetic friction between the two blocks is uc =0,250. What is the force of contact between the two blocks ??

i understand what to do if there was one block,.. but two ?
 
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boupidou said:
What is the force of contact between the two blocks?
Two blocks are in contact on a horizontal table. A force is applied on one of the blocks at a 30 degree angle (from the horizontal). The system moves towards the right. M1 = 2,00 kg and m2 = 1,00 km and F=60N and the kinetic friction between the two blocks is uc =0,250. What is the force of contact between the two blocks ??

i understand what to do if there was one block,.. but two ?

Welcome to the PF.

Always start with free body diagrams (FBDs). Do one for each block, and post what you have.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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