What is the force required to lift a car using hydraulic pistons?

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To lift a car weighing 12,000 N using hydraulic pistons, the force applied to the smaller piston must be calculated based on Pascal's principle, which states that pressure is constant throughout a closed system. The pressure exerted by the large piston supporting the car must equal the pressure exerted by the small piston. Given the diameters of the pistons, the required force on the smaller piston can be determined using the formula for pressure (force/area). The areas of the pistons can be calculated from their diameters, allowing for the necessary force to be computed. Understanding these principles is crucial for effectively using hydraulic systems in lifting applications.
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This is the last one I need some help with...

What force must be applied to a small cylinder piston with a diameter of .32m to lift a car weighing 12,000 N that is supported by the piston in a large cylinder that has a diameter of 1.4m? Assume that there is an enclosed chamber in common between the two pistons and that the chamber is filled with hydraulic oil.

Thanks
 
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Hint: Pascal's principle implies that the pressure must be the same for both pistons.
 

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