What is the formula for calculating the surface area of a sphere using calculus?

springo
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Homework Statement


Calculate the area for 3D sphere.

Homework Equations


I know there's this formula for surface of revolution:
A=2\pi\int_{a}^{b}f(x)\sqrt{1+ f'(x)^2}\:\mathrm{d}x

The Attempt at a Solution


I thought of dividing the the sphere into slices, each of which contains a ring.
The length of each ring is 2\cdot\pi\cdot r, with r=\sqrt{R^2-x^2}.
We could then integrate:
\int_{-R}^{R}2\pi\sqrt{R^2-x^2}\:\mathrm{d}x=4\pi\int_{0}^{R}\sqrt{R^2-x^2}\:\mathrm{d}x=\pi R^2
But this is not correct so there must be something wrong...

PS: Just out of curiosity, is there any way to prove the formula for the surface are of an n-sphere using calculus? (the one with Γ)
 
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The integral which you computed is (obviously) for area based on your answer. This is because you're taking a whole bunch of rings with an infinitely small width and summing them up from 0 to R. Geometrically think of it as taking a ring and fitting successively smaller rings inside of it until the point at which all the rings together resemble a single solid. That is why you are computing the area instead of surface area.

http://en.wikipedia.org/wiki/Hypersphere see the portion on volume.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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