What is the Initial Speed of a Baseball Thrown at a 45° Angle?

AI Thread Summary
To find the initial speed of a baseball thrown at a 45° angle over a distance of 250 ft, the horizontal and vertical components of velocity must be considered. The horizontal motion is described by the equation x = (v0 cos 45°)t, while the vertical motion includes gravity, represented as y = (v0 sin 45°)t - (1/2)(9.8)t². The discussion emphasizes the need to set up a system of equations using the known displacements for both x and y. Participants clarify the use of units and the correct approach to solving the equations. The conversation concludes with encouragement to solve the equations for initial velocity and time.
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Homework Statement



A baseball player throws a ball a distance of 250 ft. If the ball is released at an angle of 45°with the horizontal, find its initial speed.

Homework Equations





The Attempt at a Solution


I don't know where to begin. All i know is that speed is the norm of velocity. Help?
 
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Suppose the initial speed is v0. What are the vertical & horizontal components of the velocity.
 
x=(v0cos 45°)t
y=(v0sin 45°)t
 
close. You forgot that the y equation has acceleration due to gravity, so that's \frac{-9.8}{2}t^{2}.

And is that how I'm supposed to do math equations here? Cuz I am relatively new (I signed up earlier, I just never used it till now).
 
Yeah, that's how you do it. :smile: And thank you. I should use (32/2)t2 since the unit is feet. Correct?
 
oh yeah, sorry but that, but glad I could help. :smile:
 
So what do i do next? Differentiate?
 
oh i thought you got it. Sorry. You know that x displacement is 250 ft, and y displacement is 0. If you plug that in, you'll find you have a system of two equations with two variables--initial velocity and time. I'm sure you can solve from there. :wink:
 
Thank you so much! :smile:
 
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