What Is the Initial Temperature of Copper in a Mixed Substance System?

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The discussion revolves around calculating the initial temperature of copper in a mixed substance system involving aluminum and ethyl alcohol. The user attempted to apply the heat transfer equation Q=McT but arrived at an incorrect initial temperature of -130 C. They correctly identified the need to convert all measurements into consistent units and set up the heat balance equation, accounting for heat lost by aluminum and gained by ethyl alcohol. However, confusion remains regarding the placement of copper in the equation and how to accurately represent its heat transfer. The user seeks clarification on the correct approach to solve for the initial temperature of copper.
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Homework Statement



What is the initial temperature of copper if, 11 g aluminum at 200 C and 21 g of copper are dropped into 46 cm^3 of ethyl alcohol at 15 C. The final temperature of the system is 22 C.




Homework Equations



Q=McT

The Attempt at a Solution



My work : Qal+Qcu+Qea=0, and solved for the intial temperature. I got -130 C which was wrong. To find the mass of ethyl alcohol, i used volume and density. Volume is 790 kg/m^3
 
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Try converting everything into the same units (eg kg)
 


i converted everything and got this forumla

m1 * s1 * t1 + m2 * s2 * t2 + = m1 * s1 * tf + m2 * s2 * tf + m3 * s3 * tf

m1= aluminum
m2=coppper
m3=ethtyl alcohol,

i just can't get the write answer.
 


In Q=mcT , 'T' is the change in temperature
 


yea, i took that into account, so i did heat loss=heat gained, and the heat lost was by the aluminum, and i know the ethyl alcohol gained heat, but I am not sure what side the copper would go on
 


Al goes from 200 to 22
Cu goes from T to 22
Ethyl goes from 15 to 22

So
m_al * c_al * (200-22) + m_cu * c_cu * ( T-22) + m_eth * c_eth * (15-22) = 0
 
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