What is the kinetic energy in joules of a 950-lb motorcycle moving

AI Thread Summary
The discussion revolves around calculating the kinetic energy of a 950-lb motorcycle moving at 50 mph and determining the ratio of kinetic energy when the speed decreases to 25 mph. The kinetic energy formula KE = 1/2 mv² is applied, resulting in a kinetic energy of approximately 1.1×10^5 joules at 50 mph. When the speed changes to 25 mph, the ratio of kinetic energies K1 (at 50 mph) to K2 (at 25 mph) is calculated to be 0.25. Additionally, it is noted that this type of problem is more suited for a homework section rather than a general discussion forum, highlighting a misplacement of the topic.
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1. Homework Statement
1. What is the kinetic energy in joules of a 950-lb motorcycle moving at 50 mph ?

2. If the speed of the motorcycle changes from 50 mph (with kintic energy K1) to 25 mph (with kinetic energy K2), what is the ratio of K1 to K2?


2. Homework Equations

KE=1/2mv2


3. The Attempt at a Solution
1. 1.1×10 5 J
2. k1/k2= 0.25
 
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You already posted this in the homework section, this area isn't for homework problems, and this problem has nothing to do with chemistry.

You hit the trifecta.
 

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