What Is the Kinetic Energy of a 950-lb Motorcycle Moving at 50 mph?

AI Thread Summary
The kinetic energy of a 950-lb motorcycle moving at 50 mph is calculated using the formula KE = 1/2mv², resulting in approximately 1.1×10^5 joules. When the motorcycle's speed decreases from 50 mph to 25 mph, the ratio of kinetic energy K1 to K2 is determined to be 0.25. This indicates that the kinetic energy at 25 mph is one-fourth that at 50 mph. The calculations confirm the relationship between speed and kinetic energy, emphasizing the quadratic nature of the velocity in the kinetic energy formula. Understanding these principles is essential for solving similar physics problems.
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Homework Statement


1. What is the kinetic energy in joules of a 950-lb motorcycle moving at 50 mph ?

2. If the speed of the motorcycle changes from 50 mph (with kintic energy K1) to 25 mph (with kinetic energy K2), what is the ratio of K1 to K2?


Homework Equations



1. KE=1/2mv2
The answer I got for this problem was 1.1×10 5 J

The Attempt at a Solution



2.k1/k2= 0.25
 
Physics news on Phys.org
Yeah, those seem about right...
 
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