grog
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Homework Statement
Find the length of the curve r(t) = <2t3/2 , cos 2t, sin 2t>, for 0<= t <=1
Homework Equations
L = \int\sqrt{(dx/dt)^2+(dy/dt)^2+(dz/dt)^2}dt
The Attempt at a Solution
(dx/dt)2 = (3t1/2)2
(dy/dt)2 = (-2 sin(2t))2
(dz/dt)2 = (2 cos(2t))2
\int\sqrt{9t+4sin^2 (2t) + 4 cos^2 (2t)}dt
and since sin^2 + cos^2 = 1, that reduces to:
\int\sqrt{9t+4}dt
I found a site that had an identity for integrals with square roots, and this resembles number 6 on the list:
http://www.sosmath.com/tables/integral/integ4/integ4.html
so using that identity, I get
2\sqrt{(9t+4)^3} / 27 evaluated from 0 to 1
Is my approach correct, and if so, should I just keep these integrals on hand, or do I need to memorize all those forms?
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