What Is the Locus of Vertex A in a Right Triangle with Hypotenuse 5 Units?

  • Thread starter Thread starter aisha
  • Start date Start date
  • Tags Tags
    Points
AI Thread Summary
In a right triangle ABC with a hypotenuse BC measuring 5 units, the locus of vertex A can be determined by recognizing that the hypotenuse serves as the diameter of the circumscribing circle. The circle's equation can be derived from the radius, which is half the hypotenuse, resulting in a radius of 2.5 units. This leads to the equation x^2 + y^2 = 6.25, which represents the set of points for vertex A. The discussion highlights confusion around deriving the locus and the relationship between the triangle's geometry and the circle. Understanding these concepts is crucial for solving locus problems in geometry.
aisha
Messages
584
Reaction score
0
In a right triangle ABC, the hypotenuse BC is 5 units. Determine an equation for the locus of points for the vertex A. What will a trace of these points look like? AHHHH all these locus questions I don't have a clue I drew the triangle with BC as the hypotenuse but I don't know what else to do. PLz help me someone please :redface:
 
Physics news on Phys.org
Geometric hint: In any right triangle, the hypotenuse is the diameter of the circumscribing circle- that is, a circle with the hypotenuse as diameter will pass through the right angle vertex.
 
Don't you mean radius?
 
I feel like I don't have enough information only 5 units, I see how a circle can be drawn around the right angle triangle with the diameter=hypotenuse but I don't know how to determine an equation for the set of points for the vertex A. What do I do?

Is this correct? x^2+y^2=6.25 for the equation
 
Last edited:
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top