What is the Magnitude of F2 in a Hinged Beam Torque Problem?

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SUMMARY

The discussion centers on calculating the magnitude of force F2 in a static equilibrium problem involving a massless hinged beam. Given the parameters θ = 28.0°, L1 = 2.30 m, L2 = 1.00 m, and F1 = 31 N, the correct formula derived for F2 is F2 = (F1 * L2 * sin(θ)) / (L2 * cos(θ)). The calculated value of F2 is 7.17 N. A query regarding the torque dependency of F1 on L2 instead of L1 was raised but not addressed in the solution.

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Homework Statement



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The massless bar, hinged at A, is inclined at an angle θ = 28.0° and subjected to horizontal and vertical forces F1 and F2, as shown. If L1 = 2.30 m, L2 = 1.00 m, F1 = 31 N, and the beam is in static equilibrium, what is the magnitude of F2?


Homework Equations



T=Fr

The Attempt at a Solution



sum of forces and torques must be null
forces
F1+Rx=0
F2+Ry=0
torques
F2L2cosθ-F1L2sinθ=0
F2=F1L2sinθ/(L2cosθ)
F2=31*1*sin28/(2.30*cos28)=7.17 N
 
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Are you sure the torque produced by F1 about point A depends on L2 and not L1?
 
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