What is the mass of the ball held steady by a horizontal force?

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To determine the mass of a ball held steady by a horizontal force of 9.5 N at an angle of 16°, the equations of motion are applied. The horizontal component of the force is calculated using Fx = 9.5 cos 16, while the vertical component is Fy = 9.5 sin 16. The equilibrium condition leads to the equation Fx + Fy - w = ma, where w represents the weight of the ball. Clarification is sought regarding the exact statement of the question and the relevance of a related post about a suspended ball. The discussion emphasizes the need for precise information to solve the problem accurately.
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A horizontal force, F, holds a ball steady. Given F = 9.5 N, and θ = 16°, calculate the mass of the ball.

F=ma=0
Fx = 9.5 cos 16
Fy = 9.5 sin 16
Fx + Fy -w = ma
 
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If the force is horizontal, then what is the angle theta? Is this the exact statement of the question as you were given it?
 
look at my suspended ball post that has the picture..this post got messed up.
 
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