A meter stick blances horizontally on a knife-edge at the 50.0 cm mark. With two 5.00 g coins stacked over the 12.0 cm mark, the stick is found to balance at the 45.5 cm mark. What is the mass of the meter stick? I know it is going to be having equal torques. The torque on one side should be .01 kg*9.8 m/s^2* .335 m = .03283 N*m + the torque of the .335 m of meter stick. The other side is just the torque of the .455 m of stick. I'm not sure how to calculate the torque of the meter stick.