What is the maximum amplitude of oscillation of the system

AI Thread Summary
The discussion centers on calculating the maximum amplitude of oscillation for a system where block P undergoes simple harmonic motion with a frequency of 1.5 Hz, while block B rests on it with a static friction coefficient of 0.6. The derived formula for maximum amplitude is A = (μ_s * mg) / (m * (2πf)²), resulting in a maximum amplitude of 6.62 cm to prevent block B from slipping. Participants clarify the correct form of the acceleration equation, confirming that a = -ω²A is appropriate, with the negative sign indicating direction. The focus remains on ensuring that block B remains stationary relative to block P during oscillation.
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Homework Statement


A large block P executes horizontal simple harmonic motion as it slides across a frictionless surface with a frequency f = 1.5 Hz. Block B rests on it, as shown in the figure, and the coefficient of static friction between the two is 0.6. What is the maximum amplitude of oscillation of the system so that block B dos not slip?


Homework Equations


a=-\omega ^2*A

\omega = 2\pi f


The Attempt at a Solution



a=\omega ^2*A

\frac{F}{m}=(2\pi f)^2*A

A=\frac{\mu _s*N}{m*(2\pi f)^2}

A=\frac{\mu _s*mg}{m*(2\pi f)^2}

A=6.62~cm

Do I get it right?

Thanks
 
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It looks good to me!
I haven't seen that acceleration formula before, so I'm no expert on this.
 


Hi Delphi51

It's formula for maximum acceleration of simple harmonic motion. Thanks a lot for your reply.
 


a = - w^2 * A or a = w^2 *A??

which is right??
 


SAT2400 said:
a = - w^2 * A or a = w^2 *A??

which is right??

a=-\omega ^2 A is right because acceleration is vector. The negative sign indicates that the direction of the acceleration is in the opposite direction of the direction of motion of the particle.

In my case, I just need the numerical value so I omit the negative sign
 
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