What is the maximum distance and velocity of a charge in an electric field?

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A charge of -0.061 C moving at 54 m/s in an electric field of 888 N/C is analyzed for its maximum distance and velocity. The force exerted on the charge can be calculated using F=qE, leading to a solution based on conservation of energy principles. The initial confusion stemmed from not recognizing the simplicity of applying basic mechanics to the problem. Ultimately, the problem can be solved effectively with standard high school physics techniques. Understanding the force acting on the charge clarifies the approach needed to find the required distances and velocities.
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Homework Statement



A charge of -0.061 C is intiialy moving to the right with a velocity of 54m/s. It is moving in an electric field of 888N/C to the right, and has a mass of 0.72 kg. What is the maximum distance the charge moves to the right? What velocity does it have when it returns to the origin? What velocity does it have at x=5.75m?


Homework Equations



I don't know how to start.



The Attempt at a Solution



I tried using the electric field E=kq/r2but I can't get the solution.

I been looking at this problem blankly for a good two hours now and I could not find anything with google. Here is the link to the problem and solution.

http://books.google.com/books?id=vN...the origin has a magnitude of 845 N/C&f=false

Page 96 question 3.46
 
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This problem might sound a little harder than it actually is.

All you need to notice that an electric field exerts a force on a charged particle given by

\vec{F}=q\vec{E}

Once you consider that force, the problem can be solved with the usual high school mechanics techniques. (conservation of energy, anyone?)
 
Ty, I got the same solution as the book. I guess I was over thinking such a simple problem.
 
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