What Is the Maximum Power on an Impedance Z?

AI Thread Summary
The discussion focuses on calculating the maximum power delivered to an impedance Z using Thevenin's theorem. The user initially miscalculated the power, suspecting errors in the impedance or voltage values. After confirming the Thevenin values, they explored the maximum power theorem for complex impedance, realizing that the imaginary part of the load impedance should cancel out the source impedance's imaginary component. This led to the correct power calculation of P=64, confirming that only the real part is relevant for maximum power. The conversation emphasizes the importance of accurately matching impedance for optimal power transfer.
crom1
Messages
57
Reaction score
1

Homework Statement


Find the maximum power on a impedance Z.

Homework Equations

The Attempt at a Solution


I got as Thevenin impedance Zt=4+j4 and Ut= 32 V, but since my solution for power is wrong, something is wrong with either impedance or voltage (or both).
If point A is above Z, and point B is under Z, looking from A to B I get for impedance:
First j4 , then since I have current source in of the branches, I ignore impedances in that branch and get j4+(j4-j4+4) and since there is voltage source I ignore 2-j12.
For Thevenin voltage, I tried with superposition, and if potential of B=0, I get that for A:
$$ \varphi_A= 16 \angle 0 + 4 \angle 0 \cdot 4 + 4 \angle 0 \cdot j4 + 4 \angle 0 \cdot (-j4)=32 $$
 

Attachments

  • zadatak.png
    zadatak.png
    7.1 KB · Views: 410
Physics news on Phys.org
Your Thevenin values look okay. How did you calculate the maximum power?
 
  • Like
Likes crom1
I=Ut/(Z+Zt)=2-j2 , P=I^2 Z = 32-32i = 32 sqrt(2) , And the solution says 64.
 
What value did you give to the load impedance Z?
 
  • Like
Likes crom1
Z=Zt=4+j4
 
crom1 said:
Z=Zt=4+j4

Check the maximum power theorem for complex impedance. I think you'll find that the imaginary part of the load should nullify the source impedance's imaginary component.
 
  • Like
Likes crom1
You're right. I now get P=64-j64, do I now just take real part to get P=64?
 
crom1 said:
You're right. I now get P=64-j64, do I now just take real part to get P=64?
Yup.
 
  • Like
Likes crom1
Back
Top