What is the minimum wavelength of x-rays produced by a 50 kV emf?

AI Thread Summary
The discussion centers on calculating the minimum wavelength of x-rays produced by a 50 kV emf. Initially, the user expresses confusion about the relevant formulas and seeks assistance. They later discover the relationship through Bremsstrahlung, identifying the formula λ = hc/(50 keV). This equation indicates that the energy of the electron is converted into photon energy, allowing for the calculation of minimum wavelength. The conclusion emphasizes that the derived wavelength represents the maximum photon energy scenario, accounting for potential energy losses.
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Homework Statement


An x-rays tube is connected to a 50 kV emf. Calculate the minimum wavelength that one can find in the radiation spectra that the tube produces.

Homework Equations


No idea! This is why I ask help here.

The Attempt at a Solution


Stuck at start. I've searched in google and wikipedia about calculating the wavelength of x-rays in function of the voltage across the emf, but I didn't find any formula.
So if you either know a page or a formula, feel free to share.Edit: Nevermind I find out in wikipedia about Bremsstrahlung. It gives me \lambda = \frac{hc}{50 k eV}.
 
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The theory is that the energy of one electron is transferred to one photon. There may be some loss of energy, so the theory actually gives the minimum wavelength (maximum photon energy) case.
Energy of electron = energy of photon
qV = hc/λ
 
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