What is the molar heat of self-decomposition of nitric acid?

  • Thread starter Thread starter James Essig
  • Start date Start date
  • Tags Tags
    Acid Heat
AI Thread Summary
The discussion centers on the molar heat of self-decomposition of nitric acid, specifically seeking the value for anhydrous nitric acid. While the exact value is not readily available online, the decomposition reaction of nitric acid is outlined as 4 HNO3(aq) -> 4 NO2(aq) + O2(g) + 2 H2O(l). It is noted that anhydrous nitric acid is rarely found in pure form due to its sensitivity to heat, shock, and light. To estimate the heat of decomposition, one can use the heats of formation for the involved compounds, suggesting a calculation approach for determining the desired value.
James Essig
Messages
68
Reaction score
2
TL;DR Summary
I am trying to find the molar heat of self-decomposition of nitric acid.
I am curious as to what is the value of the molar heat of self-decomposition of nitric acid.

I've searched online and cannot seem to find the above value.

Essentially, I am looking for the value for anhydrous nitric acid although I am aware that the acid is generally not provided in pure form due to its sensitivity to heat, shock, and bright light.
 
Chemistry news on Phys.org
The reaction you want is 4 HNO3(aq) -> 4 NO2(aq) + O2(g) + 2 H2O(l). You can probably calculate a decent heat of decomposition using the heats of formation of the compounds involved.
 
It seems like a simple enough question: what is the solubility of epsom salt in water at 20°C? A graph or table showing how it varies with temperature would be a bonus. But upon searching the internet I have been unable to determine this with confidence. Wikipedia gives the value of 113g/100ml. But other sources disagree and I can't find a definitive source for the information. I even asked chatgpt but it couldn't be sure either. I thought, naively, that this would be easy to look up without...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!
Back
Top