What Is the Nuclear Binding Energy of N-14 in Joules per Mole?

AI Thread Summary
The nuclear binding energy of N-14 is being calculated, with a mass deficit of 0.11278 and an atomic mass of 14.00307. The initial conversion of the mass deficit into kilograms was attempted, but there is confusion regarding the correct units for the calculation. It is clarified that the mass of one mole of nitrogen atoms is approximately 14.00307 grams, not in kilograms. The discussion emphasizes the importance of using the correct mass unit for accurate binding energy calculations. Proper understanding of these conversions is crucial for determining the nuclear binding energy in joules per mole.
bree1622
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What is the nuclear binding energy of N-14 in joules per mole of nuclei?
The mass deficit is 0.11278. Atomic mass is 14.00307. Total mass is 14.11585.
I keep getting stuck after converting and substituting it into the equation.
First I converted the mass deficit into kilograms. 0.11278 =1.1278 × 10^-1KG. Then I put into equation. E=mc2=1.1278 × 10^-1 kgmol × (2.998×108ms)^2 . I am not quite sure if this is right so far or what to do next. Any help is greatly appreciated. Thanks!
 
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bree1622 said:
First I converted the mass deficit into kilograms. 0.11278 =1.1278 × 10^-1KG.
Is that so? What is the mass of a mole of nitrogen atoms, for example?
 
mjc123 said:
Is that so? What is the mass of a mole of nitrogen atoms, for example?
Is one mole of nitrogen 28g?
 
I said one mole of nitrogen atoms, so the answer is 14 g, or to be more precise 14.00307 g. But the point is the same. The atomic weight is the mass in g (not kg) of 1 mole. So the mass deficit is not 1.1278 x 10-1 kg/mol.
 
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