What Is the Optimal Geometry for a Concrete Column Supporting 1250 Tonnes?

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SUMMARY

The optimal geometry for a concrete column supporting 1250 tonnes at a height of 100 meters requires careful consideration of stress distribution and material efficiency. The maximum allowable stress in concrete is 15 MPa, leading to a calculated diameter of 1.1 meters based on the formula $$\sigma = \frac{F}{A}$$. The discussion emphasizes that the cross-sectional area can vary with height, suggesting a non-uniform shape may minimize material usage while maintaining structural integrity. Participants are encouraged to explore the implications of varying the cross-section along the height of the column.

PREREQUISITES
  • Understanding of concrete stress limits, specifically 15 MPa maximum allowable stress.
  • Familiarity with basic structural engineering principles, particularly load calculations.
  • Knowledge of cross-sectional area calculations and their impact on structural design.
  • Ability to apply calculus concepts to derive stress functions based on height.
NEXT STEPS
  • Research the principles of variable cross-section design in structural engineering.
  • Learn about the stress distribution in non-uniform columns and its implications.
  • Explore advanced concrete design techniques for optimizing material usage.
  • Study the relationship between height, load, and cross-sectional area in tall structures.
USEFUL FOR

Civil engineers, structural designers, and students in engineering disciplines focusing on concrete structures and load-bearing designs will benefit from this discussion.

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When building a tall support, often the self weight of the support must be considered. For an optimal support, the volume of material, and hence the cost, will be a minimum. If the maximum allowable stress in concrete is 15 MPa, determine the optimal geometry of a column 100 metres tall made of concrete to support a mass of 1250 tonnes at its top. Hint: think of the shape of the CN tower
There's no textbook for this course, so we're expected to use common sense to answer these questions...
$$\sigma = \frac{F}{A}=\frac{\pi D^2/4\cdot H\cdot W+1250\cdot 10^3 \cdot 9.81}{\pi D^2/4} $$
W=25 Kn/m, and putting all the information in, I get diameter is 1.1m. Is that right, and I was told that the radius is different at the top, not sure what to do.
 
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Rido12 said:
When building a tall support, often the self weight of the support must be considered. For an optimal support, the volume of material, and hence the cost, will be a minimum. If the maximum allowable stress in concrete is 15 MPa, determine the optimal geometry of a column 100 metres tall made of concrete to support a mass of 1250 tonnes at its top. Hint: think of the shape of the CN tower
There's no textbook for this course, so we're expected to use common sense to answer these questions...
$$\sigma = \frac{F}{A}=\frac{\pi D^2/4\cdot H\cdot W+1250\cdot 10^3 \cdot 9.81}{\pi D^2/4} $$
W=25 Kn/m, and putting all the information in, I get diameter is 1.1m. Is that right, and I was told that the radius is different at the top, not sure what to do.

Hey Rido! (Smile)

It appears you have already made the assumption that the support is a massive cylinder.
Suppose we make no assumptions about the shape yet, and just assume a cross section of $A$.
And suppose we do not make the assumption that the cross section is constant, but instead is a function of height. That is $A=A(y)$.

What formula would yet get for the stress at height $y$? (Wondering)

And since we want to use a minimal amount of material, suppose this stress is equal to the maximum stress at each $y$.
What can you deduce from that?
 

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