What is the origin of the minus sign in the derivatives of an oscillating body?

AI Thread Summary
The discussion centers on the derivatives of the position function s(t) for an oscillating body, where the first derivative is v = -Aωcos(ωt) and the second derivative is a = -Aω²sin(ωt). The user questions the origin of the negative sign in the second derivative, suggesting that the first derivative should be positive. The confusion arises from the nature of oscillatory motion, where the velocity and acceleration can have opposite signs depending on the phase of the oscillation. The negative sign in the second derivative indicates that acceleration is directed opposite to the position when the object is at maximum displacement. Understanding these signs is crucial for accurately describing the motion of oscillating systems.
Ugnius
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Homework Statement
Body of mass 0.2kg is oscillating. A = 5cm , w=π rad/s , t = 1/6 s. Find the force and momentum.
Relevant Equations
s(t) = Asin(wt)
I know it is a quite simple task.
p = mv and F=ma.
All i need to do is find the normal and double derivatives of s(t). But here's the problem , i have the answers and they state that first derivative is v =
-Awcoswt and second is -Aw^2sinwt. Everything is quite clear to me, but I am wondering can someone explain where the minus before A comes from?
 
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It's a mistake, ##\frac{ds(t)}{dt} = A\omega \cos{\omega t}##, whilst ##\frac{d^2s(t)}{dt^2} = -A\omega^2 \sin{\omega t}##.
 
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