What Is the Phase Difference Between Points on a Stationary Wave?

AI Thread Summary
The phase difference between points on a stationary wave, represented by the equation y = 0.3cos(12x)sin(t), is determined by the spatial variation of the wave. For the specified points at x = 0.1m and x = 0.5m, the phase difference is 0 radians, as both points correspond to the same position on the wave. To verify this, one can calculate the wave's value at these points or graph the wave to visually assess the phase difference. Understanding the concept of phase difference in wave motion and practicing similar problems can enhance comprehension. Seeking assistance from a teacher or tutor is also advisable for those needing further clarification.
Sanosuke Sagara
Messages
102
Reaction score
0
A stationary wave is represented by

y= 0.3cos 12x sin t

(a)What is phase difference between the points where x =0.1m and x=0.5m ?

Can anybody give suggestion for me to solve this question ?I have think for this question for a long time.Thanks for anybody that spend sometime on this question.
 
Last edited:
Physics news on Phys.org
All you care about is the spatial variation, so rewrite your equation like this:
y= A cos 12x

Now what "phase angle" (in radians) is obtained at x = 0.1m and x = 0.5m?
 


The phase difference between two points on a wave is the difference in the position of the wave at those points. In this case, the equation given is for a stationary wave, meaning the points are not moving. Therefore, the phase difference between x = 0.1m and x = 0.5m is 0 radians, as both points have the same position on the wave.

To solve this question, you can use the equation given to calculate the value of y at x = 0.1m and x = 0.5m and then find the difference between these two values. Alternatively, you can plot the wave on a graph and measure the distance between these two points to find the phase difference.

I would also recommend reviewing the concept of phase difference in wave motion and practicing similar problems to gain a better understanding. Additionally, you can seek help from a teacher or tutor if you are still struggling with this concept.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top