What is the polar form of the given complex number without using the argument?

AI Thread Summary
The discussion revolves around converting the complex number z = -7i into polar form without using the argument. The user initially attempts to express it as 7i sin(-π/2 + 2πn) but faces issues with web assignments rejecting this format. There is confusion regarding the definition of the argument, as opinions vary on its range. The user considers alternative angles like 3π/2 and seeks clarification from their teacher. The conversation highlights the challenges of understanding polar representation in complex numbers.
cragar
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Homework Statement


Write the given complex number in polar form first using an argument where theta is not equal
to Arg(z)
z=-7i

The Attempt at a Solution


7isin(\frac{-\pi}{2}+2\pi n)
The weird part about this problem it asks me to not use the argument, The argument is the smallest angle of the complex number, So I added 2 pi to it, but it tells me I am wrong on my web assign, the only other thing I can think of is taking out the generic n and just adding 2 pi to it. [/B]
 
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cragar said:
7isin(\frac{-\pi}{2}+2\pi n)
That's not what I understand by polar form.
 
z=x+iy=rcos(x)+irsin(x), that's not polar form
 
cragar said:
z=x+iy=rcos(x)+irsin(x), that's not polar form
My mistake, I was thinking of the exponential form.
It's not clear to me which specific variants you tried, like 7i sin(-π/2), 7i sin(3π/2).
As far as I can make out, there is not universal agreement whether Arg is defined to be in the range (-π, π] or [0, 2π).
 
I tried 7isin(-pi/2) ,and the one with a generic 2*pi*n, I might have to wait till my teacher gets back to me on e-mail, because I am not sure what my web assign is looking for, I might try 3*pi/2 and then add 2*pi to it, Just wanted to make sure I was interpreting it correctly . thanks for the replies
 
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