What is the Potential at the Origin for a Uniformly Charged Semi-Circle?

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The discussion focuses on calculating the electric potential at the origin due to a uniformly charged semi-circle with charge density lambda and radius R. The potential is derived using the formula dV = k*dq/R, where dq is expressed as (lambda)*R*d(theta). The integral of this expression from 0 to pi results in the final potential at the origin being V = (lambda)/(4*epsilon 0). The calculations are confirmed to be correct by the original poster. The solution effectively demonstrates the application of electrostatics principles in determining potential from a continuous charge distribution.
brad sue
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I have this problem for homework and I would like to check my work:

Charges are distribyted with uniform charge density (lambda)along a semi circle of radius R, centered at the origin of a coordinate system.
What is the potential at the origin?


I did this:
dV=k*dq/R where k=1/4*pi*(epsilon 0)


but dq=(lambda)*R*d(theta) theta is the small angle between two position on the semi circle.

pi
then V =| k*(lambda)*R*d(theta) / R (integral from 0 to pi)
0
After computation I found: V=(lambda)/(4*epsilon 0)

Thank you
 
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