What is the power factor in a series circuit?

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Homework Help Overview

The discussion revolves around calculating the power factor in a series circuit, specifically examining the relationship between resistance, impedance, and power factor calculations.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the method of calculating the power factor and question the accuracy of specific values used in the calculations. There is a focus on the derivation of impedance and its relation to the power factor.

Discussion Status

Some participants have provided calculations and expressed uncertainty about the methods used. There is an acknowledgment of correct answers, but also a critique of the approaches taken. Multiple interpretations of the calculations are being explored.

Contextual Notes

Participants are questioning the precision of numerical values and the assumptions behind the calculations, particularly regarding the impedance and its components.

hidemi
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Homework Statement
A series circuit consists of a 15-Ω resistor, a 25-mH inductor, and a 35-μF capacitor. If the frequency is 100 Hz the power factor is:

The answer is 0.45
Relevant Equations
PR / Pavg = Irms^2 * R / Irms^2*Z
I calculated in the following and got the correct answer. However, I wonder whether this way is correct or not. Thanks!

PR / Pavg = Irms^2 * R / Irms^2*Z = 15 /33.36 = 0.45
 
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Hi,

hidemi said:
and got the correct answer
So how did you get the 33.36 ? From 15/0.45 ? Then the answer is per se correct, but 'the way' is not :wink:

And you have me wondering why you type 33.36 and not 33.33 :cool:

##\ ##
 
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BvU said:
Hi,

So how did you get the 33.36 ? From 15/0.45 ? Then the answer is per se correct, but 'the way' is not :wink:(15^2

And you have me wondering why you type 33.36 and not 33.33 :cool:

##\ ##
z=√[15^2 + (100*2π*25*10^-3 - 1/(100*2π*35*10^-6))^2]
BvU said:
Hi,

So how did you get the 33.36 ? From 15/0.45 ? Then the answer is per se correct, but 'the way' is not :wink:

And you have me wondering why you type 33.36 and not 33.33 :cool:

##\ ##
My detailed calculation is as attached.
 

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Yes the power factor is ##\cos\phi=\frac{R}{Z}##.
 
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Delta2 said:
Yes the power factor is ##\cos\phi=\frac{R}{Z}##.
Ok Thank you, I understand.
 

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