What is the probability that a defective part came from supplier B?

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Discussion Overview

The discussion revolves around calculating the probability that a defective part came from supplier B, given the probabilities of defects from two suppliers, A and B. It includes a breakdown of the probabilities associated with each supplier and the overall defect rates in the context of a manufacturing scenario.

Discussion Character

  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • Some participants propose calculating the probability of a defective part being from supplier B using the formula (.025 * .2).
  • Others argue that the total probability of a defective part must account for both suppliers and should sum to 1, suggesting a need for a different approach to calculating conditional probabilities.
  • One participant expresses confusion about the calculations and seeks clarification on the reasoning behind the probabilities.
  • Another participant emphasizes that if the probabilities do not add up to 1, the calculations must be reconsidered.
  • There is a suggestion to analyze the problem using a hypothetical scenario of producing 1000 products to better understand the proportions of defective parts from each supplier.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct method for calculating the probability that a defective part is from supplier B. Multiple competing views and interpretations of the calculations remain unresolved.

Contextual Notes

Participants express uncertainty regarding the correct application of conditional probability and the need for clarity in the calculations. There is a reliance on hypothetical scenarios to explore the problem further.

fireboy420
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The ABC manufacturing company purchases a certain part from two suppliers (A supplier & B supplier). The parts received from the suppliers are used to produce the company’s major product. The parts received from the suppliers are either defective or good parts. The A supplier provides 80% of all parts. Given that a part is from the A supplier, there is 2.5% probability that the part is defective. Given that a part is from the B supplier, there is a 1% chance that the part is defective.

a) If a defective part is found, what is the probability that it is from supplier B?
>>>(.025*.2)?
b) What is the probability that the company’s major product is defective?
>>>(.025*.2)+(.8*.01)?
 
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(b) looks right. You need to think a little harder about (a). Think about this: if a defective part is found, it must be from either A or B. So the probability that a defective part is from A and the probability that it is from B have to add up to 1. If you calculate the probability that a defective part is from A in the same way as you did for B, then add the two answers, do you get 1?
 
Thanks for your reply. Ur answer is still not clear to me. Sorry!
 
What part don't you understand?
 
My understanding: (.8*.025)+(0.2*0.01)

But that doesn't add to 1.
 
fireboy420 said:
My understanding: (.8*.025)+(0.2*0.01)

But that doesn't add to 1.
Exactly. So that means you can't be calculating the conditional probability in the right way. Any calculation you try, you can do this check, and if it doesn't add up to 1, you know you need to think again.

Now, you know that the chance of a defect is (.025*.2)+(.8*.01). You know that in some of those cases the bad part was from company A, and in some it was from company B. What are the proportions?
 
Then isn't it what I had was right? (0.025*.2) since B is only 20% supplier.
 
sorry its 0.2*0.01 right?
 
fireboy420 said:
Then isn't it what I had was right? (0.025*.2) since B is only 20% supplier.
That's the proportion of bad B's in ALL the products, good and bad. What's the proportion of bad B's in just the bad products?

Try this: say we made 1000 products. How many of those contain the B part? How many contain a bad B part? How many contain an A part? How many contain a bad A part? What's the total number of bads in the 1000? Of those bads, how many are B's and how many are A's?
 

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