What is the Q value for the symmetric fission of 236U?

[matt222]

Homework Statement

what is the Q value for the symmetric fission of 236U?

Homework Equations

M(Z,A)=Zmp+Nmn-B

The Attempt at a Solution

I don't understand the question by saying symmetric fission, is it mean we have the reaction which is

236U=118Ru+118Ru
so the Q from he reaction will be obtained from this what I did or

 

[kuruman]

That's what it means. The daughter fragments are identical.

 

[matt222]

But how the Q value for the symmetric fission of U236 calculated? I calculated from what the question said two doughters 118Ru so I found the answer which is about 158MeV, Now if we talk about the Q value for fission to 96Sr and 140Xe I got Q about 184MeV, Why we have difference now in the both cases I really couldn't understand to it.

 

[kuruman]

The binding energy of the parent nucleus, BE1, is greater than the sum of the binding energies of the daughters, BE2+BE2. The difference is Q. You need to calculate some binding energies here, namely BE1 and BE2 and then subtract.