What is the R/a Ratio for a 1% Deviation in Electric Field at Point x=a/2?

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The discussion revolves around calculating the ratio of the plate radius (R) to the separation between the plates (a) for a 1% deviation in electric field at point x=a/2. The electric field is expressed using the charge density and the constant E_0, with the formula provided for the field between two disks. Participants express uncertainty about how to approach the problem and whether the equation's terms are correctly interpreted. Clarifications are sought regarding the numerator in the equation, as it affects the ability to determine the ratio. The conversation highlights the complexity of the question and the need for precise understanding of the electric field equations.
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NOT HOME WORK QUESTION (itsfrom last year exam question)

Homework Statement


electric field between two disk of radius of R and at distance D=a/2 is given by the following
n=charge density (Q/A) E_0= the constant 8.85*10^-12

E=(n/E_o)((1- (a/2)/(((a/2)^2)+(R^2))^1/2

for what value of the ratio of the plate radius to separation between the plates does the electric field at point x=a/2 deffer by 1percent from the result n/E_o for infinite sheets?
R/a=...

Homework Equations



the equation for infinite sheet is E=n/2E_o

The Attempt at a Solution


not sure how to approach this question
is it R/2a=0.01 then R/2a*0.01=50?
please can some one explain this to me!
 
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What the question means is that E = 0.99 n / \epsilon

or it could also be E = 1.01 n / \epsilon.

E is given in terms of a and R, so finding the ratio should not be a problem.

Are you sure, though, that it is " 1 - a/2 " in the numerator? In this case, finding the ratio would be impossible.
 

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