What is the Radius of a Long Solenoid with a Given Induced Electric Field?

  • Thread starter Thread starter raisen
  • Start date Start date
  • Tags Tags
    Radius Solenoid
raisen
Messages
1
Reaction score
0

Homework Statement



For a long solenoid, the magnetic field strength within the solenoid is given by the equation B = 5.0t T, where t is time in seconds. If the induced electric field outside the solenoid is 11 V/m at a distance 2.0m from the axis of the solenoid, find the radius of the solenoid.

Homework Equations



E_inside = r/2 |dB/dt|


The Attempt at a Solution



I know how to calculate the electric field outside the solenoid, but how can I associate the magnetic field inside of it with the electric field outside?
 
Physics news on Phys.org
raisen said:

Homework Statement



For a long solenoid, the magnetic field strength within the solenoid is given by the equation B = 5.0t T, where t is time in seconds. If the induced electric field outside the solenoid is 11 V/m at a distance 2.0m from the axis of the solenoid, find the radius of the solenoid.

Homework Equations



E_inside = r/2 |dB/dt|


The Attempt at a Solution



I know how to calculate the electric field outside the solenoid, but how can I associate the magnetic field inside of it with the electric field outside?

Assume that the magnetic flux through the 2.0 m circle extends only over the cross-sectional area of the solenoid.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top