What is the RATE of Rotation help

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The discussion revolves around calculating the rate of rotation of a tumble dryer basket with a diameter of 0.65 meters, where clothes fall away at a 60-degree angle from the vertical. Participants explore various formulas, including centripetal force equations, to derive the velocity and ultimately the rotation rate in revolutions per minute. Confusion arises regarding the conversion of linear velocity to angular velocity and the correct use of the radius in calculations. The consensus indicates that the correct rate of rotation is approximately 37 revolutions per minute, with some participants mistakenly calculating it as 74. The key takeaway is the importance of correctly applying the radius and understanding the relationship between linear and angular velocity in such problems.
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What is the RATE of Rotation! help!

An automatic tumble dryer has a 0.65m diamter basket that rotates about a horizontal axis. As the basket turns, the clothes fall away from the basket's edge and tubmle over. IF the colthes fall away from the basket at a point 60 degrees from the vertical, what is the rate of rotation in units of revolutions per minute.


i thought this problem would be extremely simple.

I was wrong :)

First i get

V^2 / rg = tan theta
so i get

Vc^2 = rg tan theta
soif ifind Vc i get 1.785

Now this wouldn't make snese...
does someone else have a different Apporpach
 
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ok i can't get mass from anything. what do i do?

it has tobe something like 0.65 / x = tan theta or something?
 
F=mv^2/r

At sixty degrees the vertical part of this centripetal force is provided solely by the weight of the clothes ie mg.

thus mv^2/r*cos60 = mg, am I wrong?

v= sqrt(r*g/cos60) = 2.53m/s? Then remember you have to make it revs/min

cannot see why you are using tan
 
the answer is 37revs/minute
i did get 2.53m/s and then multiplied it by 60/2pi
wrong wrong :(
 
Yeah I get 74 revs/minute =/

I did 2.53/r to get it in rads/sec and then /2pi * 60 = 74...

2 times 37, strange
 
maybe because the problem gave it in diameters and u used that.
i'm still trying to get it
 
wait i still don'tget how uget 2.53m/s to 74rev/min

2.53 / (2pi x 60) doesn't work nor (2.53/2pi) x 60
 
no i used radius and I told you 2.53/r to get radians per seconds.

2.53/2pi*60 doesn't mean anything. What you want is

2.53/r/2pi*60 to get 74
 
ok so any idea why it is 74 instead of 37?
 
  • #10
Unfortunately no clue =(
 
  • #11
can you give me the exact equation that gives 74.
ive tried so many.. it's so weird.

so 2.53m/s is in seconds so i multiply it by 60 to make it in minutes.
so it turns 2.53x60 m/minutes
now since its in meters i have to divide it by 2pi to make it by revolutions
this gives me 24... Not 74... :(

am i looking for r? what did i do wrong?
 
  • #12
What is 2.53 it is velocity, IE m/s

why would 2.53/2pi give you revs/s? It does not. However 2.53/r gives you rads/s which divided by 2pi gives you revs/s

The exact equation as stated before is!

2.53/r/2pi*60 to get 74
 
  • #13
(2.53 x 60) / (2 * pi * .65) = 37.1688006

I think you're forgetting r.
 
  • #14
BSCS said:
(2.53 x 60) / (2 * pi * .65) = 37.1688006

I think you're forgetting r.

But r is .65/2 is it not?
 
  • #15
"0.65m diamter", you are correct.
 
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