What is the relationship between curl and surface integrals in vector calculus?

[we are the robots]

Curl and Surface Integral (help!)

Hello people!
I've been working on this problem, but I can't find how differentials of V on the left side of the equation appear.

***
Show, by expansion of the surface integral, that (see attached image).
Hint: choose the volume to be a differential volume, dx dy dz .
***

Here d(sigma) is a vector surface element, V is a vector field, and d(tau) is a infinitesimal volume element.
Well, from the right side of the equation is clear that derivatives of V will appear, but I can't do the same on the left side, where I only get components of the vector field multiplied by infinitesimal area elements.
Using the lower part of the fraction, some of these elements "disappear", but no hint of the derivatives of V appear to me. Any ideas?

By the way, is there any way to put images inside the message?
Thanks!

 

[matt grime]

Here's the tex version (faq in general physics forum)

\lim_{\int d\tau \to 0} \frac{\int_S d\sigma\wedge V}{\int d\tau} = \nabla\wedge V

I'm not sure that you really want the limit as the integral of d\tau goes to zero since the integral of d\tau is just the volume (though you've not said what you're integrating d\tau over so I'm guessing here)

Click on the image to see the code for it

 

[M98Ranger]

Hello!

Curl and surface integrals are important concepts in vector calculus. Let's break down the problem and try to understand it step by step.

Firstly, let's define what curl and surface integrals are. Curl is a mathematical operator that measures the rotation of a vector field. It is represented by the symbol "∇ x" and is also known as the "cross product". Surface integral, on the other hand, is a type of integral that calculates the flux of a vector field through a surface. It is represented by the symbol "∫∫F⋅d(sigma)" where F is the vector field and d(sigma) is the vector surface element.

Now, let's move on to the problem at hand. The hint suggests choosing the volume to be a differential volume, dx dy dz. This means that we can consider the volume to be a small cube with sides dx, dy, and dz. By expanding the surface integral, we are essentially breaking down the surface into smaller and smaller elements until we reach the infinitesimal element d(sigma).

The left side of the equation represents the curl of the vector field V. To understand how derivatives of V appear on this side, we can use the definition of curl and expand it using the product rule. This will result in the derivatives of V appearing in the equation.

To put images in your message, you can use the "Attach file" button or copy and paste the image directly into the message.

I hope this helps! Keep practicing and you will get the hang of it. Good luck!