Engineering What is the relationship between skin depth and AC resistance?

Click For Summary
The discussion clarifies the calculation of AC resistance, specifically addressing the skin depth formula. It corrects the area used in the calculations, stating that A should be 20/10^6 m^2. The skin depth at 500 kHz is confirmed to be 0.0894 mm, not the previously mentioned value. Accurate calculations are crucial for understanding the relationship between skin depth and AC resistance. This highlights the importance of precise measurements in electrical engineering contexts.
Callum Plunkett
Messages
27
Reaction score
8
Homework Statement
At 1 kHz, the skin depth in copper is 2 mm. Determine the a.c. resistance
at 500 kHz and at 10 MHz of 20 cm lengths of copper conductors having
the following cross sections:
(a) round section 20 mm2
(b) square section 20 mm2
(c) rectangular section 1 mm × 20 mm
Take the conductivity of copper as 5.8 × 107 Sm–1
Relevant Equations
Rac=0.25(1+D/s)Rdc
Untitled.png
 
Physics news on Phys.org
Rdc is not correct. Take A=20/10^6 m^2 [in sqr.m not in sqr.mm]
and δ500kHz=0.0894 mm [2*√(1/500)] not 0.2*√(1/500)
 
Last edited:
Thank you for the help! much appreciated.
 
I have a question that I couldn’t fully understand its logic. The professor asked us to calculate the shear resistance and moment about the X and Y axis, using the given cross-section and the values of compressive and tensile stresses. I understand how to get the moment, but I’m confused about how to find the shear resistance from these stresses. Could you explain or clarify the method?

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
2K
Replies
36
Views
3K