What is the relationship between work, power, and lifting an object?

Thread starter MoreZitiPlease
Start date Mar 27, 2008
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Power Work

AI Thread Summary

Work is calculated using the formula W = Fd, where F is the force applied and d is the distance moved. For a 1 kg object lifted 1.5 meters, the force is equal to the weight, F = mg, which equals 9.81 N. Thus, the work done is W = 9.81 N * 1.5 m, resulting in approximately 14.7 joules. Power is then calculated using P = W/t, leading to a power output of about 5.88 watts when the lift occurs over 2.5 seconds. The calculations confirm the relationship between work, power, and lifting an object.

Mar 27, 2008

MoreZitiPlease

If I lift an objct that weighs 1kg a distance of 1.5 meters in 2.5 seconds, what is my work and power done?

Can you show me how you did it?

I don't know how

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Mar 27, 2008

rock.freak667

Homework Helper

Start off with the definition of Work done. How do you calculate it?

Mar 27, 2008

MoreZitiPlease

w=fd

i got 14.7 for work

and

5.88 for power

Mar 27, 2008

Snazzy

So you do know how. ;)

Mar 27, 2008

rock.freak667

Homework Helper

F=mg=1*9.81= #

W=Fd=#*1.5= ____ J

P=W/t and your answers seem to be correct so.

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