What is the Required Centripetal Acceleration for a Stone to Reach 25 Meters?

AI Thread Summary
To determine the required centripetal acceleration for a stone to reach a distance of 25 meters when thrown from a sling of length 1.3 meters, the initial velocity must be calculated based on the time the stone is in the air. Assuming a release height of 2.7 meters, the time of flight can be derived from projectile motion equations. The centripetal acceleration can then be calculated using the relationship ac = v^2/r, where v is the velocity at release and r is the radius of the sling. The discussion emphasizes the importance of understanding the stone's trajectory and the necessary calculations to achieve the desired distance. Accurate calculations will ensure the stone reaches the target distance effectively.
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Homework Statement



You plan to throw stones by using a sling of length 1.3 m which you whirl over your head. Suppose you wish to throw a stone a distance of 25 m. What must be the centripetal acceleration of the stone just before its release if it is to reach this distance? Assume that the release height is 2.7 m.

Homework Equations



ac = v^2/r = (w^2)r = (4((pi)^2)r)/(T^2)

The Attempt at a Solution



I really don't know how to start this problem
 
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First figure out how fast you have to throw the stone to reach that distance. Hint: Assuming the stone is released horizontally, how long is it in the air?
 
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