What is the resulting amperage from a Leyden jar discharge?

AI Thread Summary
Calculating the current from a Leyden jar discharge can yield extremely high amperage figures, especially if using ideal conditions. The discussion highlights the challenge of relating charge to resulting amperage accurately. A near-ideal capacitor discharging through a perfect conductor can produce a momentary pulse of current that approaches infinite amperes. However, real-world non-ideal components will reduce this current and extend its duration. Understanding these factors is crucial for accurate calculations.
Juanka
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I need to figure out how to correctly calculate the Current being created from a leyden jar I have. I am attaching a print screen of a matchcad calculation that shows what I have done. However, I am calculating extremely high amperage. I believe my calculation is correct down to my charge, but I do not know how to correctly relate my charge to the resulting amperage. Have a look! any suggestions please!
 

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If you discharge a near-ideal capacitor with an almost perfect conductor, there will be a momentary pulse of current approaching infinite amperes. Non-ideal components reduce the amplitude, and extend the duration.
 
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