What is the Secondary Side Current in a Transformer-Based Energy Meter Design?

  • Thread starter Thread starter harshasunder
  • Start date Start date
  • Tags Tags
    Load Transformer
AI Thread Summary
In the discussion about the secondary side current in a transformer-based energy meter design, the focus is on understanding the current flow when using a voltage divider circuit connected to a transformer. The current on the secondary side is determined by the chosen resistors and the secondary voltage, not by the high currents present in the primary circuit. The energy IC mentioned, an ADE7752B, requires both voltage and current inputs for accurate power measurement. A current transformer is necessary to measure the actual load current, which was acknowledged but not initially included in the design. The participant expresses increased confidence in their design after clarifying these points.
harshasunder
Messages
9
Reaction score
0
Hi
Im building an energy meter and I have a doubt about the voltage channel I am using to measure voltage. Basically there is a transformer that is connected between line and neutral and on the secondary side, there is voltage dividing resistor circuit to step down the voltage to the levels needed for the energy ic. The question is, how much current is flowing on the secondary side?The actual wires that I am measuring the energy from are using huge currents, 60 A etc but since there's no load connected to the transformer (Im not even using the transformer to power the Ic), there's only a current that depends on the resistors used for voltage dividing flowing on the secondary side right?
any comments would be welcome
Thanks
Harsha
 
Engineering news on Phys.org
I haven't understood what this "energy ic" does.
The current in your "secondary side" depends just on the resistors you choose to put there and the secondary voltage. This seems so obvious that I feel I must have missed something. Have I?
If you want to measure the power consumed then you also need a current transformer in series with your 60A cable.
 
hi
thanks for replying
the energy ic is an ade7752B analog device ic. It measures 3 phase power if you feed it voltage and current inputs from each phase. Yes, i know you need a current transformer, I just didnt mention it.
I wanted to be sure about the current on the secondary side and so the question. thanks for the reply, I am now more confident of my design.
thanks
Harsha
 
Very basic question. Consider a 3-terminal device with terminals say A,B,C. Kirchhoff Current Law (KCL) and Kirchhoff Voltage Law (KVL) establish two relationships between the 3 currents entering the terminals and the 3 terminal's voltage pairs respectively. So we have 2 equations in 6 unknowns. To proceed further we need two more (independent) equations in order to solve the circuit the 3-terminal device is connected to (basically one treats such a device as an unbalanced two-port...
suppose you have two capacitors with a 0.1 Farad value and 12 VDC rating. label these as A and B. label the terminals of each as 1 and 2. you also have a voltmeter with a 40 volt linear range for DC. you also have a 9 volt DC power supply fed by mains. you charge each capacitor to 9 volts with terminal 1 being - (negative) and terminal 2 being + (positive). you connect the voltmeter to terminal A2 and to terminal B1. does it read any voltage? can - of one capacitor discharge + of the...
Back
Top