What is the slope of the ground in the landing zone?

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SUMMARY

The discussion focuses on calculating the slope of the ground in the landing zone for skiers leaving a jump at 28 m/s and an angle of 9.5 degrees below the horizontal. The horizontal distance to the landing zone is 55 m, and the skiers' trajectory makes an angle of 3 degrees with the ground upon landing. The key equations used include the kinematic equations for linear motion, specifically the horizontal and vertical displacement equations. The solution involves determining the time of flight and the corresponding x-y coordinates to find the slope.

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Cantworkit
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[SOLVED] linear motion

Homework Statement


Skiers leave a ski jump at 28 m/s, at an angle of 9.5 degrees below the horizontal. Their landing zone is a horizontal distance of 55 m from the end of the jumo The ground is contoured at that point so that the skiers trajectories make an angle of only 3 degrees with the ground on landing. What is the slope of the ground in the landing zone?


Homework Equations


tan theta = y/x
x = x0 + v0t + 1/2gt^2
y = y0 + y0t + 1/2 gt^2

The Attempt at a Solution



t = (x - x0)/v0 = (x - x0)/v0cos9.5 = 2s
From here I can solve for the velocity vector at the landing, but I do not see how to solve for the x-y coordinates
 
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Cantworkit said:

Homework Statement



From here I can solve for the velocity vector at the landing, but I do not see how to solve for the x-y coordinates

Won't v point in the same direction as the skis? As I read the problem, the angle of the slope is three degrees less than this.
 

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