What is the Solution for W, X, Y, and Z?

Thread starter r-soy
Start date Mar 23, 2010

AI Thread Summary

To verify the solution for values w, x, y, and z, substitute them into the left matrix and perform the multiplication. If the resulting matrix matches the one on the right, the solution is confirmed as correct. The discussion emphasizes the importance of checking calculations independently. This method ensures accuracy in solving matrix equations. Following these steps will help validate the answer effectively.

Mar 23, 2010

r-soy

Hi

I want check my answer

The question ande the answer on the attachment >>

Physics news on Phys.org

Mar 23, 2010

Mark44

Mentor

Insights Author

Can't you check for yourself? You have values of w, x, y, and z. Just substitute them into the left matrix at the start of your problem, and do the multiplication. If you get the matrix on the right, then your solution is correct.

Thread 'Family of lines that are at a distance of 5 from the origin'

I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

View full post »

Thread 'Making the denominator of a certain fraction real'

Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...

View full post »