What is the spring constant of each spring

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Homework Help Overview

The discussion revolves around determining the spring constant for springs in a compact car, with a focus on oscillation frequency and mass distribution across the springs. The problem involves concepts from mechanics, specifically related to oscillatory motion and spring dynamics.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the calculation of the spring constant based on the car's mass and oscillation frequency. There is an attempt to clarify the distribution of mass across multiple springs and how that affects the calculations. Questions arise regarding the correct interpretation of the spring system and the implications of dividing the spring constant.

Discussion Status

The discussion is active, with participants providing calculations and questioning the accuracy of their approaches. Some guidance has been offered regarding the division of the spring constant by the number of springs, but there is no explicit consensus on the final values or methods used.

Contextual Notes

Participants are working under the assumption that the mass of the car is evenly distributed across the four springs, and there is a need to clarify the mass per spring for accurate calculations. The original poster expresses uncertainty about their calculations, indicating a potential misunderstanding in the application of the formulas.

rayhan619
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Homework Statement



A compact car has a mass of 1200 kg. Assume that the car has one spring on each wheel, that the spring are identical, and that the mass is equally distributed over the four springs. draw a picture of the situation.
a) what is the spring constant of each spring if the empty car bounces up and down 2.0 times per second?
b) what will be the cars oscillation frequency while carrying four 70 kg passengers.

Homework Equations



f = 1/2pie(k/m)^sq root

The Attempt at a Solution



m = 1200 kg
f = 2 hz

a) k = (2*pie*f)^2 * m = (2*3.14*2hz)^2*1200 kg = 189304.32 N/m

b) m = (4*70)+1200 kg = 1480 kg

f = (1/2*pie)(189304.32 Nm^-1/1480 kg) = 1.8 hz

im not sure where I messed up.
 
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rayhan619 said:
a) k = (2*pie*f)^2 * m = (2*3.14*2hz)^2*1200 kg = 189304.32 N/m
There are four springs, not one giant spring.
 
so divide k by 4?
 
Yes.
 
so
a) k = (189304.32 N/m)/4 = 47326.08 N/m

and
b) f = (1/2*pie)(47326.08 Nm^-1/1480 kg)^sq. root = 0.9 hz

is it right?
 
rayhan619 said:
so
a) k = (189304.32 N/m)/4 = 47326.08 N/m
OK.

and
b) f = (1/2*pie)(47326.08 Nm^-1/1480 kg)^sq. root = 0.9 hz
No. What's the mass per spring?
 

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