What Is the Stopping Potential When Using a Cut-Off Frequency Filter?

AI Thread Summary
When using a cut-off frequency filter, the stopping potential depends on whether electrons can escape from the metal. If the light frequency is at or below the cut-off frequency, no electrons will be emitted, meaning no stopping potential is needed. The correct answer is that the stopping potential is zero, as no electrons escape when the cut-off frequency is not reached. The confusion arises from the assumption of the experimental setup, which implies that only frequencies above the cut-off would allow electron emission. Understanding the relationship between light frequency, work function, and electron emission is crucial in this context.
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Homework Statement



Assume the same set-up to measure the stopping potential Vs through different filters. Suppose a filter allowed through only light of frequency fo (the cut-off frequency) or lower. In this case, what would the stopping potential be?
1) you cannot tell, since different electrons will escape with different speeds
2) you need no stopping potential because no electrons escape from the metal
3) greater than zero: electrons escape, and must be stopped from drifting to the anode
4) zero

Homework Equations



KE = hf - W
Also: if the cutoff frequency of the light is not reached, no electrons are emitted from the metal.

The Attempt at a Solution



With the reasoning above concerning cutoff frequency, I chose answer choice 2. However, this was marked incorrect.

Any suggestions or comments would be greatly appreciated! :)
 
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